Download Fast Fourier Transform and Its Applications by Sergej Rjasanow; Olaf Steinbach PDF

By Sergej Rjasanow; Olaf Steinbach

The quick Fourier rework (FFT) is a mathematical process well-known in sign processing. This booklet specializes in the appliance of the FFT in numerous components: Biomedical engineering, mechanical research, research of inventory marketplace info, geophysical research, and the traditional radar communications box.

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47) that is, if h(t) is defined as the mid value at a discontinuity, then the inversion formula stilI holds. Note that in the previous examples we carefully defined each discontinuous function consistent with Eq. 47). 4 ALTERNATE FOURIER TRANSFORM DEFINITIONS It is a well-established fact that the Fourier transform is a universally accepted tool of modern analysis. Yet, to this day, there is not a common definition of the Fourier integral and its inversion formula. 49) 1 See Appendix A. The definition of the impulse response is based on the continuity of the testing function h(t).

The Fourier Transform 20 Hlf) hld- A COl 12wfot) f', A f' ,f\, f', I I I I I t I V V V Rlf) f\ (1 I V s Chap. 9 Fourier transform of A cos(at). f ' dt H(f) = ~ = 2 ~ = 2 f"" [~2""fo, + e-j2.... za(f - fo) A (f + fo) + 28 where arguments identical to those leading to Eq. 36) have been employed. fO' + ~e -j2.... za(f - fo) + A28(f + fo) ~A A cos(2'TTfot) ~ is illustrated in Fig. 9. 10 Fourier transform of A sin(at). 42) Sec. 3 Existence of the Fourier Integral 21 Similarly, the Fourier transform pair (Fig.

38 Fourier Transform Properties Chap. 3 H(t) hIt) Y2[H(t-fo)" H(f.. 5 Frequency-shifting property. Sec. ltl ·51. -41. -31. -21. -I. I. 21. 31. 41. 51. ltl -51. -41. -31. -21. -I. I. 21. 31. 41. 51. ltl· cos (271j3I. It] -51. -31. -21. -I. I. 21. 31. 41. 51. 61. 6 Examples of sum and difference frequencies produced by frequency mUltiplication. Fourier Transform Properties 40 Chap. 5 ALTERNATE INVERSION FORMULA r The inversion formula of Eq. 25) where H*(f) is the conjugate of H(f); that is, if H(f) = R(f) + jI(f), then H*(f) = R(f) - jI(f).

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