 The research of combinatorics on phrases is a comparatively new examine quarter within the fields of discrete and algorithmic arithmetic. that includes an easy, available variety, Algorithmic Combinatorics on Partial phrases offers combinatorial and algorithmic thoughts within the rising box of phrases and partial phrases. This booklet features a wealth of routines and difficulties that assists with numerous set of rules tracing, set of rules layout, mathematical proofs, and software implementation. it is also various labored instance and diagrams, making this a priceless textual content for college students, researchers, and practitioners looking to comprehend this complicated topic the place many difficulties stay unexplored.

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Additional resources for Algorithmic Combinatorics on Partial Words

Sample text

If i ∈ H(z), then we prove that x(i) = y(i) as follows. We have z(i) ⊂ x(i) and z(i) ⊂ y(i), z(i + k) ⊂ y(i) and z(i + k) ⊂ y(i + k), z(i + 2k) ⊂ y(i + k) and z(i + 2k) ⊂ y(i + 2k), .. z(i + (m − 1)k) ⊂ y(i + (m − 2)k) and z(i + (m − 1)k) ⊂ y(i + (m − 1)k), Combinatorial Properties of Partial Words 55 z(i + mk) ⊂ y(i + (m − 1)k) and z(i + mk) ⊂ x(i). Here seqk,l (i) = (i, i+k, . . , i+mk, i) and z(i)z(i+k)z(i+2k) . . z(i+mk)z(i) does not contain consecutive holes and does not contain two holes while not 1-periodic since z is not {k, l}-special.

2: The construction of seq6,8 (0). 7 If k = 6 and l = 8, then seq6,8 (0) = (0, 6, 12, 4, 10, 2, 8, 0). 2. It can be seen that this path selects positions gcd(6, 8) = 2 letters apart, beginning with position 0. To fully verify periodicity, it will be necessary to generate another sequence beginning at i = 1, which is seq6,8 (1) = (1, 7, 13, 5, 11, 3, 9, 1). No other sequence is necessary, for if we calculated seq6,8 (2) we simply would obtain a permutation of the first sequence since it already contains the position 2.

3. 3 Let u and v be partial words. Prove that if v is primitive and v ⊂ u, then u is primitive as well. 4 S Let u be a partial word of length p, where p is a prime number. Prove that u is not primitive if and only if α(u) ≤ 1. 5 Construct a partial word with one hole of length 12 over the alphabet {a, b} that is weakly 5-periodic, weakly 8-periodic but not 1-periodic. 6 Let u be a word over an alphabet A, and let v = ua for any letter a in A. Prove that p(u) ≤ p(v). 7 For partial words u and v, does u ↑ v imply u ⊂ v. 